GCSE Maths Foundation

Algebra

43 free practice questions with explanations

PassNova has 43 free GCSE Maths Foundation practice questions on Algebra, each with a clear explanation. Practise them in the browser with instant feedback — 100% free, no sign-up, on any device. Updated for 2026.

Sample questions

Algebra: example questions & answers

12 worked examples with answers and explanations below. Practise all 43 Algebra questions free in the browser, with instant feedback on every answer.

  1. Simplify 3a + 2b + a - b.

    • A4a + b
    • B3a + 2b
    • C5ab
    • D4a + 3b

    Answer: Collect like terms: 3a + a = 4a, and 2b - b = b. So 3a + 2b + a - b = 4a + b.

  2. Expand 3(x + 4).

    • A3x + 4
    • B3x + 12
    • Cx + 12
    • D3x + 7

    Answer: Multiply each term inside the bracket by 3: 3 × x + 3 × 4 = 3x + 12.

  3. Solve x + 5 = 12.

    • Ax = 17
    • Bx = 7
    • Cx = -7
    • Dx = 2.4

    Answer: Subtract 5 from both sides: x + 5 - 5 = 12 - 5, so x = 7.

  4. Solve 2x = 16.

    • Ax = 8
    • Bx = 18
    • Cx = 14
    • Dx = 32

    Answer: Divide both sides by 2: 2x ÷ 2 = 16 ÷ 2, so x = 8.

  5. If y = 3x + 2, what is y when x = 4?

    • A10
    • B12
    • C14
    • D9

    Answer: Substitute x = 4: y = 3(4) + 2 = 12 + 2 = 14.

  6. Simplify 5x × 2y.

    • A7xy
    • B10xy
    • C10x + y
    • D5xy × 2

    Answer: 5x × 2y = (5 × 2) × (x × y) = 10xy.

  7. Expand 2(3x - 5).

    • A6x - 5
    • B6x - 10
    • C5x - 5
    • D3x - 10

    Answer: 2 × 3x = 6x, and 2 × (-5) = -10. So 2(3x - 5) = 6x - 10.

  8. Solve 3x - 2 = 10.

    • Ax = 4
    • Bx = 2.67
    • Cx = 8
    • Dx = 12

    Answer: Add 2 to both sides: 3x = 12. Divide by 3: x = 4.

  9. Factorise 6a + 9.

    • A3(2a + 3)
    • B3(a + 3)
    • C6(a + 1.5)
    • D2(3a + 4.5)

    Answer: Find the highest common factor: HCF(6, 9) = 3. So 6a + 9 = 3(2a + 3).

  10. What is the next term in the sequence 2, 5, 8, 11, ...?

    • A12
    • B13
    • C14
    • D15

    Answer: The sequence increases by 3 each time (2→5, 5→8, 8→11). So the next term is 11 + 3 = 14.

  11. What is the nth term formula for the sequence 3, 6, 9, 12, ...?

    • An + 3
    • B3n
    • Cn + 2
    • D3n + 3

    Answer: Each term is 3 times its position: 1st term = 3(1) = 3, 2nd term = 3(2) = 6, 3rd term = 3(3) = 9. The nth term is 3n.

  12. Expand (x + 2)(x + 3).

    • Ax² + 5x + 6
    • Bx² + 6x + 5
    • Cx² + 6
    • D2x + 5

    Answer: x(x+3) + 2(x+3) = x² + 3x + 2x + 6 = x² + 5x + 6.

Start practising Algebra →