Maths: Statistics & Probability
12 free practice questions with explanations
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PassNova has 12 free GCSE Equivalency Tests practice questions on Maths: Statistics & Probability, each with a clear explanation. Practise them in the browser with instant feedback — 100% free, no sign-up, on any device. Updated for 2026.
Maths: Statistics & Probability: example questions & answers
12 worked examples with answers and explanations below. Practise them in the browser with instant feedback on every answer.
The scores of five students are 12, 15, 9, 15 and 19. What is the mean score?
- A15
- B14✓
- C10
- D13
Answer: The mean is the total divided by the number of values: (12 + 15 + 9 + 15 + 19) ÷ 5 = 70 ÷ 5 = 14. 15 is the mode and also the median; 10 is the range (19 − 9).
For the same five scores — 12, 15, 9, 15 and 19 — what is the median?
- A12
- B14
- C15✓
- D9
Answer: Put the values in order: 9, 12, 15, 15, 19. The median is the middle value, which is 15. 14 is the mean, not the median.
A bag contains 4 red, 3 blue and 3 green counters. One counter is picked at random. What is the probability that it is blue?
- A1/3
- B3/10✓
- C7/10
- D3/7
Answer: There are 4 + 3 + 3 = 10 counters and 3 of them are blue, so the probability is 3/10. 7/10 is the probability of not picking blue, and 3/7 ignores the green counters.
A fair six-sided dice is rolled twice. What is the probability of getting a 6 both times?
- A1/12
- B1/36✓
- C1/6
- D2/6
Answer: The rolls are independent, so the probabilities multiply: 1/6 × 1/6 = 1/36. Adding the probabilities (2/6) or halving (1/12) are the usual errors.
A survey of 40 people has a mean score of 12.5. A 41st person scores 33. What is the new mean score?
- A12.5
- B14
- C13✓
- D22.75
Answer: The original total is 40 × 12.5 = 500. Adding 33 gives 533 over 41 values: 533 ÷ 41 = 13. Leaving the mean unchanged ignores the new value, and 22.75 averages the old mean with 33.
A scatter graph of hours of revision against test score shows the points rising from bottom-left to top-right. What does this show?
- AThat revision causes a higher score in every case
- BNo correlation between the two variables
- CPositive correlation between revision time and score✓
- DNegative correlation between revision time and score
Answer: Points rising from bottom-left to top-right show that as one variable increases the other tends to increase: a positive correlation. Correlation on its own does not prove that revision causes the higher score for every student.
Which average is most affected by one extremely high value in a data set?
- AThe range is an average and is unaffected
- BThe median
- CThe mean✓
- DThe mode
Answer: The mean uses every value, so a single very large value pulls it up. The median depends only on the middle position and the mode on the most frequent value, so neither shifts much; the range is a measure of spread, not an average.
The probability that it rains on a given day is 0.3. What is the probability that it does not rain?
- A0.3
- B0.7✓
- C0.6
- D1.3
Answer: The probabilities of an event and its complement add to 1, so P(no rain) = 1 − 0.3 = 0.7.
A spinner has four equal sections coloured red, blue, green and yellow. It is spun twice. What is the probability of red then blue?
- A1/2
- B1/16✓
- C1/8
- D1/4
Answer: Each spin is independent with probability 1/4 for any colour, so P(red then blue) = 1/4 × 1/4 = 1/16. Adding the probabilities would give 1/2, which is wrong for a sequence of two events.
A survey asks 'Don't you agree that the new car park is excellent?' Why is this a poor question?
- AIt is too short to gather useful data
- BIt can only be asked of people who drive and use the car park regularly
- CIt has too many possible answers to analyse in a survey of this kind of size
- DIt is a leading question that pushes respondents towards agreeing✓
Answer: Questions that suggest the expected answer produce biased results; a fair version would ask respondents to rate the car park on a neutral scale. Length and the number of answers are not the problem here.
A frequency table shows how many books 30 students read last month: 2 books (5 students), 4 books (12), 6 books (8), 8 books (5). Estimate the mean number of books, to one decimal place.
- A4.9✓
- B6.0
- C4.0
- D5.0
Answer: Multiply each value by its frequency and add: (2 × 5) + (4 × 12) + (6 × 8) + (8 × 5) = 10 + 48 + 48 + 40 = 146. Divide by the 30 students: 146 ÷ 30 = 4.87, which rounds to 4.9. Averaging the four values (5.0) ignores the frequencies.
A pie chart shows how 120 people travel to work. The 'bus' sector has an angle of 90°. How many people travel by bus?
- A40
- B90
- C30✓
- D25
Answer: A full circle of 360° represents 120 people, so 90° represents 90/360 = 1/4 of them: 120 ÷ 4 = 30.